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Minimum potential difference, Balmer series

  1. Oct 16, 2014 #1
    1. The problem statement, all variables and given/known data
    -A beam of electrons bombards a sample of hydrogen in its ground state.
    a) Through what minimum potental difference must the electrons be accelerated if only one line of the Balmer's series can be observed?

    2. Relevant equations
    V= h^2/2meλ^2 (V=potential difference)
    1/λ=R((1/n(i)^2)-(1/n(f)^2))
    3. The attempt at a solution

    ......1/(1.09*10^7((1/2^2)-(1/3^2)))=λ, λ=6.60*10^-7
    V= h^2/2meλ^2
    .....((6.626*10^-34)^2/((2*(9.11*10^-31)(1.6*10^-19)(6.60*10^-7)^2))= 3*10^-6 volts

    This is a question I got wrong on a previous homework and I am still trying to figure out how to correctly figure this out. I just am unsure if I am even doing this correctly and I have tried this in quite a few ways.
     
  2. jcsd
  3. Oct 16, 2014 #2

    TSny

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    Hello. Can you explain why you chose n(i) = 2 and n(f) = 3 ? Note that the atoms are initially in the ground state. The electrons must excite the atoms from their ground state to the appropriate energy level for which the first Balmer line can subsequently be produced.
     
  4. Oct 17, 2014 #3
    I chose 2 because that is where the Balmer lines start so that is what I assumed I must use. If that is wrong may you elaborate on where I should begin at?
     
  5. Oct 17, 2014 #4

    TSny

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    The atom cannot emit light unless it is first excited into an excited state. Where does the energy come from to excite the atom? Also, to what minimum energy level must the atom be excited in order to be able to emit one of the Balmer lines?
     
  6. Oct 18, 2014 #5
    The first excited state is -13.6Ev/4= -3.4eV is where the Balmer lines start due to the n=2 is the point after the ground state. Also you excite the atom through collisions to bump one from one state to another. Would I use E = q*V and just subtract the first state from the 2nd? Such as -13.6Ev/1.6*10^-19C - -3.4 eV/1.6*10^-19C= -6.38 *10^19 Volts would be the potential difference?
     
    Last edited: Oct 18, 2014
  7. Oct 18, 2014 #6

    gneill

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    You need to look into what the Balmer series represents (I think there's a Wikipedia article that explains the various series fairly well, if memory serves). In short, the series is a result of electrons jumping down to the 2nd state. In order to jump down to the second state they must first be kicked up to a higher state than that...
     
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