Missing Mass: What is the Mass of Block 2 in a System of Three Blocks?

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SUMMARY

The discussion focuses on calculating the mass of Block 2 in a system of three blocks, where Block 1 has a mass of 12 kg, Block 3 has a mass of 35 kg, and the tension between Block 2 and Block 3 is 111 N. The correct application of Newton's 2nd Law (F = ma) is essential for solving the problem. The tension equation 111 N = (m1 + m2)a is confirmed as accurate, but it is clarified that additional forces must be considered for Block 3's motion. The missing tension value for Block 1 is crucial for a complete solution.

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Homework Statement



Three blocks are pulled along a frictionless surface. The masses of two of the blocks and the tensions in two of the cords are given. Find the mass of the third block (Block 2).

Block 1 ------- Block 2------Block 3 ------>
Block 1: m1 = 12 kg
Block 2: m2 = UNKNOWN
Block 3: m3 = 35 kg
Tension between Block 2 and Block 3: 111 N

Homework Equations



Newton's 2nd Law: F = ma

The Attempt at a Solution



111N = (m1+m2)a = m3a <-- is this true?

Block 2, m2 = 35-12? This seems to easy to be true.
 
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That does not seem correct. You stated that the tensions in two cords are known, but only give the tension between Block 2 and 3. What is the other known tension?

Once you have that, draw free body diagrams, it might help to clear things up.
 
You said two cord tensions are given, but seem to have left one of them out here?

Sherrylee said:
111N = (m1+m2)a = m3a <-- is this true?

111N = (m1+m2)a is correct.
But it is not equal to m3a ... there are two forces contributing to m3's motion: the 111N and ____ ?
 

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