Missing Power Solving the PDE (Solution included)

  • #1
25
1

Homework Statement


upload_2016-5-1_18-56-40.png


Homework Equations




The Attempt at a Solution


integral[du]= Integral[xt ds]
xt=18s2+3sT
so,
u=Integral[18s2+3sT]
u=6s3+(3/2)s2T+C
C=eT2

This is what I did and the solution is below. I'm unsure where the missing power on the (3/2)sT went in the u(s,t) equation.[/B]
upload_2016-5-1_19-4-41.png
 

Answers and Replies

  • #2
SammyS
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Homework Statement


View attachment 100094

Homework Equations



The Attempt at a Solution


integral[du]= Integral[xt ds]
xt=18s2+3sT
so,
u=Integral[18s2+3sT]
u=6s3+(3/2)s2T+C
C=eT2

This is what I did and the solution is below. I'm unsure where the missing power on the (3/2)sT went in the u(s,t) equation.
View attachment 100096
Let's make the initial image somewhat readable:
upload_2016-5-2_9-28-36.png


You reaaly need to give a complete statement of your problem in the body of your initial post. Here, are we to assume that you are asked to solve that PDE with the stated initial condition?
 
  • #3
25
1
The goal is to solve the cauchy pde.
 

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