Missing Power Solving the PDE (Solution included)

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SUMMARY

The discussion focuses on solving a partial differential equation (PDE) using the method of integration. The user attempts to integrate the expression xt = 18s² + 3sT, leading to the solution u(s,t) = 6s³ + (3/2)s²T + C, where C = eT². The user expresses confusion regarding the missing power of (3/2)sT in the final equation. The context suggests that the problem involves the Cauchy PDE with specified initial conditions.

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zr95
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Homework Statement


upload_2016-5-1_18-56-40.png


Homework Equations

The Attempt at a Solution


integral[du]= Integral[xt ds]
xt=18s2+3sT
so,
u=Integral[18s2+3sT]
u=6s3+(3/2)s2T+C
C=eT2

This is what I did and the solution is below. I'm unsure where the missing power on the (3/2)sT went in the u(s,t) equation.[/B]
upload_2016-5-1_19-4-41.png
 
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zr95 said:

Homework Statement


View attachment 100094

Homework Equations



The Attempt at a Solution


integral[du]= Integral[xt ds]
xt=18s2+3sT
so,
u=Integral[18s2+3sT]
u=6s3+(3/2)s2T+C
C=eT2

This is what I did and the solution is below. I'm unsure where the missing power on the (3/2)sT went in the u(s,t) equation.
View attachment 100096
Let's make the initial image somewhat readable:
upload_2016-5-2_9-28-36.png


You reaaly need to give a complete statement of your problem in the body of your initial post. Here, are we to assume that you are asked to solve that PDE with the stated initial condition?
 
The goal is to solve the cauchy pde.
 

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