A Mixed quantum state of the Bose-Einstein distribution

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The discussion centers on the nature of the quantum state associated with the Bose-Einstein distribution, questioning why it is considered mixed rather than pure. Participants seek mathematical proof to support this classification and reference course materials for clarification. There is a call for specific sections in the referenced notes that address the Bose-Einstein distribution directly. The conversation highlights a need for clearer definitions and explanations regarding the mixed state concept in quantum mechanics. Overall, the thread emphasizes the importance of mathematical demonstrations in understanding quantum states.
Bertt
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Why is the quantum state of the Bose-Einstein distribution mixed and not pure? Is there any mathematical proof on this?
 
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Bertt said:
he quantum state of the Bose-Einstein distribution
What quantum state are you talking about? Do you have a reference?
 
Bertt said:
See e.g. these course notes
Where do these notes talk about a Bose-Einstein distribution? What makes you think the "Bose-Einstein distribution" is a mixed quantum state?
 
For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...

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