Graduate Mixed quantum state of the Bose-Einstein distribution

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SUMMARY

The discussion centers on the mixed quantum state of the Bose-Einstein distribution, questioning its classification as mixed rather than pure. Participants seek mathematical proof and references to support this classification. The MIT course notes on quantum theory of radiation interactions are suggested as a resource for further understanding. The conversation emphasizes the need for clarity on the definitions and characteristics of quantum states in the context of Bose-Einstein statistics.

PREREQUISITES
  • Understanding of quantum mechanics principles
  • Familiarity with Bose-Einstein statistics
  • Knowledge of mixed versus pure quantum states
  • Basic mathematical skills for quantum state analysis
NEXT STEPS
  • Review the MIT course notes on quantum theory of radiation interactions
  • Study the mathematical framework of Bose-Einstein distribution
  • Explore the differences between mixed and pure quantum states
  • Investigate applications of Bose-Einstein statistics in quantum physics
USEFUL FOR

Quantum physicists, students of quantum mechanics, and researchers interested in the properties of Bose-Einstein distributions and their implications in quantum state theory.

Bertt
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Why is the quantum state of the Bose-Einstein distribution mixed and not pure? Is there any mathematical proof on this?
 
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Bertt said:
he quantum state of the Bose-Einstein distribution
What quantum state are you talking about? Do you have a reference?
 
Bertt said:
See e.g. these course notes
Where do these notes talk about a Bose-Einstein distribution? What makes you think the "Bose-Einstein distribution" is a mixed quantum state?
 

Thread 'Two equivalent statements of time reversal symmetric Hamiltonian'

Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?
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