1. Dec 5, 2014

Dustinsfl

1. The problem statement, all variables and given/known data
I have a system of five coupled ODEs. I believe I should be able to reduce it down to four coupled ODEs, but I am not sure how. This system is modeling a quad X rotor where the arms are viewed as end loaded cantilever beams with motors attached.

2. Relevant equations

3. The attempt at a solution
\begin{align}
m_{eq}\ddot{y}_1 &= k_{eq}(y_5 - y_1) + c(\dot{y}_5 - \dot{y}_1) + F_1(t)\tag{1}\\
m_{eq}\ddot{y}_2 &= k_{eq}(y_5 - y_2) + c(\dot{y}_5 - \dot{y}_2) + F_2(t)\tag{2}\\
m_{eq}\ddot{y}_3 &= k_{eq}(y_5 - y_3) + c(\dot{y}_5 - \dot{y}_3) + F_3(t)\tag{3}\\
m_{eq}\ddot{y}_4 &= k_{eq}(y_5 - y_4) + c(\dot{y}_5 - \dot{y}_4) + F_4(t)\tag{4}\\
m_t\ddot{y}_5 &= F_1(t) + F_2(t) + F_3(t) + F_4(t) \tag{5}
\end{align}

This system is modeling the vibrations of quadrotor due to the motors spinnings. Also, I am trying to determine the initial conditions too. If we assume at $t = 0$, we have no displacement then $y_i(0) = 0$ and $\dot{y}_i = a_i\delta(t)$. My thought on the initial velocity is at $t = 0$ the rotors start running at flying speed (instantly to make the problem easier). Would this be the correct way to model the initial velocity? Also, $F_i(t) = c_i\cos(\omega t + \phi_i)$ where $c_i$ are the amplitudes, $\omega$ the rad/sec of the rotors, and $\phi$ the phase offset.

Is equation (5) correct for modeling the movement of the center of the quadrotor?

2. Dec 5, 2014

Dr.D

Do you have a picture showing the system and your coordinates?

3. Dec 5, 2014

Dustinsfl

I am using z to denote the displacement of the body (where the arms connect) only. Also, I am viewing the arms as cantilever beams with an end load.

It is just a normal X quad rotor. I have, also, made some adjustments. I think the system should be of the form:
1. I noticed I neglected gravity. Would that be simple adding the term
$-m_{eq}y_i$ to equations one to four and $-m_bz$? Or is it more
involved?
2. Do I still need $m_t\ddot{y}_5 = \sum_iF_i(t)$ any more? Is it correct in this form?

Here is one of my thoughts for final system of ODE form. Is it correct?
\begin{align}
m_{eq}\ddot{y}_1 &= k_{eq}(z - y_1) + c(\dot{z} - \dot{y}_1) - m_{eq}y_1 +
F_1(t)\\
m_{eq}\ddot{y}_2 &= k_{eq}(z - y_2) + c(\dot{z} - \dot{y}_2) - m_{eq}y_2 +
F_2(t)\\
m_{eq}\ddot{y}_3 &= k_{eq}(z - y_3) + c(\dot{z} - \dot{y}_3) - m_{eq}y_3 +
F_3(t)\\
m_{eq}\ddot{y}_4 &= k_{eq}(z - y_4) + c(\dot{z} - \dot{y}_4) - m_{eq}y_4 +
F_4(t)\\
m_b\ddot{z} &= \sum_i\bigl[F_i(t) + k_{eq}(y_i - z) +
c(\dot{y}_i - \dot{z})\bigr] - m_bz\\
m_t\ddot{y}_5 &= \sum_iF_i(t) - m_ty_5\tag{6}\\
Y &= \frac{m_bz + \sum_im_{eq}y_i}{m_t}\tag{7}
\end{align}
Is equation (6) needed? It is modeling the overall displacement of the quadrotor. Equation (7) is my constraint.

4. Dec 6, 2014

5. Dec 6, 2014

6. Dec 7, 2014

Dr.D

I did not see a single one of those figures that identified with certainty the coordinate you are using. If you cannot be bothered to draw a figure, then please don't expect too much help.

7. Dec 7, 2014

Dustinsfl

I guess I need to break it down Barney style for you. There are 4 arms so y_i where i is 1,2,3,4 are the arm displacement. I then said the body I am using z. That means the equation which isn't a constraint must be the displacement of the whole quad rotor if we view it as a rigid body. Also the arms have the rotors so the forcing functions should have been a give away too. Equation 7 is a COM constraint equation. Are you sure you are a Dr of anything?

8. Dec 7, 2014

Dr.D

If I were interested in working this problem myself, I would not need to ask for help. I'm not interested in the problem personally, so anything I have said was intended to get you thinking straight. Without a good figure, you are not likely to ever get the problem in hand.

I see some problems with your formulation, but I'm not going to try to point them out to you. It would require a figure, and you evidently consider such a thing childish and beneath your dignity.

Don't worry too much about my Ph.D., even though it is almost 50 years old. It is still quite durable.

I don't think I have any more time for you.