Modeling Bank Account Growth with Differential Equations

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SUMMARY

The discussion focuses on modeling bank account growth using differential equations, specifically with an interest rate of 4% per year. The differential equation derived is dA/dt = 4500 - 5000, where A(t) represents the account balance over time. The initial condition A(0) = 10,000 is provided, and the calculation for the account balance after 5 years incorporates both the interest and annual income, resulting in A(5) = 10000(1.04)^5 + 4500*5 - 5000*5. The hint regarding e^(1/5) = 6/5 is noted for further calculations.

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  • Ability to perform calculations without a calculator
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lordy12
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1. You have a bank account that earns 4% interest per year. You earn $4500 per year designing web pages for local businesses and spend $5000 buying CD's and computer games.
a.) Find differential equation that models account t years from now, A(t). b) If A(0) = 10,000 how much money will be in the account in 5 years?




Homework Equations





3. a. dA/dt = 4500t - 5000t b. 10000(1.04)^5 + 4500*5 - 5000*5. Is this correct? The problem for part b is that I can't use a calculator and the problem gives me a hint that e^(1/5) = 6/5/
 
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You've not used the 4% interest yet though. That says that every year 4% of your money will be added on. Can you add this into the differential equations?
 

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