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## Homework Statement

Block B with a mass of (.75kg) is on an inclined plane attatched by a pulley to Block A which has a mass of (1.5kg). The angle given is 40 degrees. The coefficient of friction of Block B on the ramp is .29. What is the acceleration?

## Homework Equations

F

_{net}=m*a

f=F

_{normal}*Coefficient of f

## The Attempt at a Solution

My solution was F

_{net}= m*a

F

_{net}= F

_{applied}- f

F

_{applied}= the weight of Block A (m*g) = 14.7N

f = f

_{x}of Block B which equals sin(40)*7.36 = 2.25

F

_{net}= 12.5

therefore a=F

_{net}/ m

m = mass of the system which is 1.5 +.75 = 2.25kg

a = 12.5 / 2.25

a= 5.56m/s/s

I don't think that this is correct. Our Physics teacher has showed us inclined plane problems with a = 0 and without Atwood's machine. He has also showed us an Atwood's Machine problem without an angle. So now I am stuck and I don't know how to accuratley solve this problem. Thanks for the help.

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