Modular Arithmetic: Solving Equations with 22x^2 = 11 mod 13

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To solve the equation 22x^2 = 11 mod 13, applying modular arithmetic simplifies the process. By substituting z = x^2, the equation transforms into a more manageable form, allowing for easier solution methods without trial and error. The discussion emphasizes the importance of understanding common modular equations, which can often be solved systematically. It also highlights that while trial and error is feasible for smaller moduli like 13, larger numbers would necessitate more efficient methods. Overall, the conversation underscores the value of structured approaches in modular arithmetic to avoid unnecessary complications.
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Homework Statement
22x^2 + 13(x + 2y)^3 = 11 has no integer solutions x and y
Relevant Equations
Module asthmatic.
I am thinking of taking modular of 13 to both sides of equation. So it will become
22x^2 is 11 mod 13.
And try all the values from x equal to zero to x equal to 11.
Is their easier way to solve it
 
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I think it is a good idea, what I would do is to define ##z=x^2## to have the equation ##az=c \pmod{m}## which is very easy to solve without trying an error (which is not a problem for this small numbers, but its always nice to have a method to solve things), and then you only need to solve ##z = x^2 \pmod{m}## which again can be done without trying an error.
 
How can I find that there's no solution using your method, there's no integer solution
 
Well, as I said, the equations ##ax=b \pmod{m}## and ##x^2=a \pmod{m}## are very common and important and you can find the solutions of both without trying and error (if you have not studied this then it's OK). Of course, that means that, if they don't have a solution you can prove it without having to try all the possibilities. (As I said, since you are working ##\pmod{13}## try and error is not a big deal, but if you were working at ##mod{97}## it would be really long, and a number with 10 digits would be impossible except maybe for a computer.)
 
"Modular asthmatic"? Doesn't modular arithmetic have enough problems without being asthmatic as well?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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