Modulus of Elasticity with shear Corrected

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SUMMARY

The discussion focuses on calculating the Modulus of Elasticity (MOE) with shear correction for wood samples using data from a Three Point Bending Test. The provided values include a force of 2400 N, deflection of 4.3 mm, span of 343 mm, and dimensions of the wood sample. The initial equation used for MOE calculation is MOE = (Force * Span^3) / (4 * Deflection * b * d^3). The final goal is to determine the corrected E value, which requires estimating the E/G ratio specific to the wood species, with a target result of 18417.95 KPa.

PREREQUISITES
  • Understanding of Three Point Bending Test methodology
  • Familiarity with the concepts of Modulus of Elasticity (MOE) and shear modulus (G)
  • Proficiency in applying mechanical equations related to material properties
  • Knowledge of significant figures in scientific calculations
NEXT STEPS
  • Research the E/G ratio for various wood species to enhance accuracy in calculations
  • Learn about the significance of significant figures in engineering calculations
  • Explore advanced methods for calculating shear correction factors in bending tests
  • Investigate the impact of varying deflection values on MOE calculations
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Students in materials science, engineers involved in structural analysis, and professionals working with wood properties in construction and design.

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I appreciate your help with this problem from a Three point Bending Test in Wood samples

Homework Statement



Force: 2400 N
Deflection: 4.3 mm
Span: 343 mm
Length: 392 mm
b: 24.01 mm
d: 24.25
MOE: 16445.15 MPa

How can I calculate the Modulus of Elasticity with shear corrected?


Homework Equations



I have this equation
First I got the MOE=(Force*Span^3)/4*Deflection*b*d^3)
then I should be able to calculate E but I don´t know how to get E/G
E=MOE*(1+(6/5)*(d/Span)^2*E/G)


The Attempt at a Solution


The result must be 18417.95 KPa
 
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I assume you must estimate the E/G ratio for the particular species of wood. If your math is correct and the solution is correct (why so many significant figures??), looks like G = .05E, but I can't help much more . Might suggest search on G and E values for different species .
 
I agree Jay's point. If deflection is 4.3 mm, then how many significant figures are reasonable for the solution? When you have worked out the answer to your question, try putting in 4.2 mm and 4.4 mm (which the deflection is NOT) and then conclude the so called accuracy of your answer...
 

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