How to Calculate Molality for a 0.5% Urea Solution at 0°C?

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To calculate the molality of a 0.5% urea solution at 0°C, first determine the mass of urea in a given volume of solution. A 0.5% solution means there are 0.5 grams of urea per 100 grams of solution. Since the density of the solution is similar to that of water, assume the mass of the solvent (water) is approximately 99.5 grams, or 0.0995 kilograms. Using the formula for molality, which is the number of moles of solute divided by the mass of solvent in kilograms, the molality can be calculated as 0.5 grams of urea (1/60 mol) divided by 0.0995 kg of water. The final molality is approximately 0.0833 mol/kg.
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Molality creating problems for me!

calculate the molality and osmotica pressur of a 0.5% solution of urea (Mol Mass=60) in water at 0 degree celsius.

R-0.0821

now my dear friends!

i have calculated successfuly the osmotic pressure in this question which is

osmotic pressure = 1.86 atm

now the problem is this that how to calculate this molality. i know that

molality = no of moles of the solute/ mass of the solvent in kilograms

but you see that here i don't have any masss of the solute given at all.

Please help me

Thanks in advance
 
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Such diluted solution has density almost identical with the density of pure water.
 
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