Calculating Molar Concentration of Diluted HCl Solution

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Discussion Overview

The discussion revolves around calculating the molar concentration of a diluted hydrochloric acid (HCl) solution after mixing a specific volume of concentrated HCl with distilled water. Participants explore the application of dilution equations and the resulting concentration.

Discussion Character

  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant calculates the molar concentration using the formula c1v1=c2v2 and arrives at 0.63 M, questioning the book's answer of 0.60 M.
  • Another participant challenges the initial assertion by pointing out a potential misunderstanding of the problem statement regarding the total volume after dilution.
  • A different participant calculates the concentration based on the total volume of 500 mL and suggests that the correct concentration is 0.60 M.
  • Further clarification is provided that the number of moles of HCl is 0.3 moles, leading to a calculation of molarity as 0.60 M.
  • There is a correction regarding the number of moles, with one participant asserting that the calculation should consider the correct conversion from moles to molarity.

Areas of Agreement / Disagreement

Participants express disagreement regarding the initial calculation of molarity, with some supporting the book's answer of 0.60 M and others advocating for 0.63 M. The discussion remains unresolved as different interpretations and calculations are presented.

Contextual Notes

There are unresolved assumptions regarding the interpretation of the dilution process and the calculations of moles and volume, which may affect the final concentration results.

fish
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If 25 mL of 12 M HCl are added to 475 mL of distilled water, what is the molar concentration of the diluted hydrochloric acid?

c1v1=c2v2
25*12=475c
c=.63 M HCL

book has the answer as .60 M HCL
Isn't the answer .63?
 
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"25*12=475c"

Think about this a moment; you've asserted something different from the problem statement, "25 mL of 12 M HCl are added to 475 mL ---."
 
Your total volume is 500ml, and you have 12 moles. 12moles/.500L is?
 
this seems to work, .30 mol/.500L = .60 M
 
Originally posted by GeneralChemTutor
Your total volume is 500ml, and you have 12 moles. 12moles/.500L is?

No u have 12/40=0.3 moles
and now volume is 500mL

therefore molarity= 0.3*2=0.60

it is right way fish
 

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