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## Homework Statement

Calculate the magnitude of the force supported by the point at A under the action of the 2.5-kN load applied to the bracket. Neglect friction in the slot.

AB = .17 m

B to force = .16 m

angle between vertical and BtoForce = 24

## The Attempt at a Solution

I found the x and y distance of the force from B

y = .16 cos 24 = .1462

x = .16 sin 24 = .0651

I tried multiplying the force by the y distance but it was incorrect.

I also found the distance from A to the force which is:

√((.17 + .0651)

^{2}+ (.1462)

^{2}) = .2768

and multiplied that by the force but that was also incorrect. Any ideas?

Any help appreciated!

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