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Moment at a point applied to a bracket
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[QUOTE="sabz333, post: 4501667, member: 487812"] [h2]Homework Statement [/h2] Calculate the magnitude of the force supported by the point at A under the action of the 2.5-kN load applied to the bracket. Neglect friction in the slot. AB = .17 m B to force = .16 m angle between vertical and BtoForce = 24[h2]The Attempt at a Solution[/h2] I found the x and y distance of the force from B y = .16 cos 24 = .1462 x = .16 sin 24 = .0651 I tried multiplying the force by the y distance but it was incorrect. I also found the distance from A to the force which is: √((.17 + .0651)[SUP]2[/SUP] + (.1462)[SUP]2[/SUP]) = .2768 and multiplied that by the force but that was also incorrect. Any ideas? Any help appreciated! [/QUOTE]
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Moment at a point applied to a bracket
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