Moment generating function and expectation

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Homework Help Overview

The discussion revolves around a random variable X with a specified probability mass function, P(j) = 2^(-j) for j = 1, 2, 3, ... Participants are tasked with computing the moment generating function (MGF) of X and using it to find the expectation of X.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to compute the MGF and expresses confusion about the relationship between the MGF and the expectation of X. Other participants provide links and affirm the approach taken, while also discussing the differentiation process involved in finding the expectation.

Discussion Status

Some participants have provided helpful resources and affirmed the strategies used in the calculations. There appears to be a productive exchange regarding the differentiation of the MGF to find the expectation, although explicit consensus on the correctness of the final answer has not been reached.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the depth of exploration into the concepts involved.

BookMark440
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Homework Statement


Let X denote a random variable with the following probability mass function:
P(j)= 2^(-j), j=1,2,3,...
(a) Compute the moment generating function of X.
(b) Use your answer to part (a) to compute the expectation of X.

Homework Equations


m.g.f of X is M (t) = E[e^tX]


The Attempt at a Solution



I computed the MGF (X) to be: e^t/(2-e^t). I need a suggestion about the next step. I'm confused about the relationship between the MGF and expectation of X.

Thanks!
 
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That link was very helpful. I completed the problem but I am a little uncertain about my strategy of finding the derivative by parts and the answer:

X has p.d.f : p(j) = 2^(-j), j=1,2,3,...

I computed the MGF for X = e^t/(2-e^t)

Then E[X] = d/dt (e^t/(2-e^t)) [evaluated for t= 0] =

numerator = (2-e^t)d/dt(e^t) - (e^t)d/dt(2-e^t)
denominator = (2-e^t)^2

Evaluating for t=0, the final answer is:
E[X] = 2

Is this the correct strategy and answer?

Thanks!
 
Hi BookMark440! :smile:

(try using the X2 tag just above the Reply box :wink:)
BookMark440 said:
Then E[X] = d/dt (e^t/(2-e^t)) [evaluated for t= 0] =

numerator = (2-e^t)d/dt(e^t) - (e^t)d/dt(2-e^t)
denominator = (2-e^t)^2

Evaluating for t=0, the final answer is:
E[X] = 2

Is this the correct strategy and answer?!

Looks good! :biggrin:
 

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