Moment of inertia cylinder problem

Click For Summary
SUMMARY

The discussion centers on a physics problem involving a 20 kg bucket of water suspended by a rope around a solid cylinder windlass with a diameter of 0.2 m and mass of 20 kg. The key equations used include the moment of inertia formula I=1/2MR^2 and the tension equation T-Mg=ma. The participant successfully solved parts (a) and (b) but encountered discrepancies in part (c), calculating the fall time as 2.47 seconds instead of the expected 7 seconds, and misinterpreted the force exerted on the cylinder by the axle, which should be twice the centripetal force.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with rotational dynamics and moment of inertia
  • Knowledge of kinematic equations for uniformly accelerated motion
  • Basic grasp of forces acting on objects in motion
NEXT STEPS
  • Review the derivation of the moment of inertia for solid cylinders
  • Study the relationship between linear and angular acceleration in rotational systems
  • Learn how to apply kinematic equations to solve for time of fall in free-fall problems
  • Investigate the forces acting on rotating objects and their implications on net force calculations
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of rotational dynamics and kinematics in real-world applications.

brendan3eb
Messages
53
Reaction score
0

Homework Statement


A bucket of water of mass 20 kg is suspended by a rope wrapped around a windlass in the form of a solid cylinder 0.2 m in diameter, also of mass 20 kg. The cylinder is pivoted on a frictionless axle through its center. The bucket is released from rest at the top of a well and falls 20 m to the water. Neglect the weight of the rope.
(a) what is the tension in the rope while the bucket is falling
(b) with what velocity does the bucket strike the water?
(c) What was the time of the fall?
(d) While the bucket is falling, what is the force exerted on the cylinder by the axle?

Homework Equations


all the basic velocity, initial velocity, etc. equations
I=1/2MR^2
T-Mg=ma


The Attempt at a Solution


I solved parts A and B easily enough. However, I am not sure if my teacher gave me the wrong answer to C. By using both v=v0+aT and y=y0+v0T+1/2aT^2 I get T=2.47 s, but the correct answer is supposedly around 7 s...

Additionally, I figured that the force of the axle on the cylinder would be the opposing force to the centripetal force ma of the cylinder, but the correct answer is twice this value..

all help would be greatly appreciated
 
Physics news on Phys.org
brendan3eb said:
I solved parts A and B easily enough. However, I am not sure if my teacher gave me the wrong answer to C. By using both v=v0+aT and y=y0+v0T+1/2aT^2 I get T=2.47 s, but the correct answer is supposedly around 7 s...
I'd say your answer is correct.

Additionally, I figured that the force of the axle on the cylinder would be the opposing force to the centripetal force ma of the cylinder, but the correct answer is twice this value..
I don't see what centripetal force has to do with anything. What forces act on the cylinder? What's the net force?
 

Similar threads

  • · Replies 40 ·
2
Replies
40
Views
6K
Replies
2
Views
2K
Replies
5
Views
2K
Replies
12
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 25 ·
Replies
25
Views
14K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
1K