Moment of Inertia Homework: Solving for Force P

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SUMMARY

The problem involves calculating the force P applied to a rope wrapped around a hollow cylinder with a weight of 55.0 N and a radius of 0.25 m. The cylinder rotates without friction and is initially at rest. After pulling the rope for 3.00 m, the end of the rope reaches a speed of 4.00 m/s. The key equations used include the relationship between linear velocity and angular velocity (v = ωr), the angular acceleration (α = τ/I), and the moment of inertia (I = MR²). The work done by the force P equals the change in kinetic energy of the cylinder.

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Homework Statement



A light, flexible rope is wrapped several times around a hollow cylinder with a weight of 55.0 N and a radius of 0.25 m, that rotates without friction about a fixed horizontal axis. The cylinder is attached to the axle by spokes of a negligible moment of inertia. The cylinder is initially at rest. The free end of the rope is pulled with a constant force P for a distance of 3.00 m, at which point the end of the rope is moving at 4.00 m/s. If the rope does not slip on the cylinder, what is the value of P?


Homework Equations



v=[tex]\omega[/tex]r
[tex]\alpha[/tex]=[tex]\tau[/tex]/I
I=MR^2

The Attempt at a Solution



Alright, I honestly don't know where to start with this problem. It's review we're doing and I know the basics of inertia but nothing past that!

Can anybody help me start?

Thanks a lot,
Peter
 
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work done by P on the cylinder = change in kinetic energy of the cylinder
 

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