Moment of Inertia/ Kinetic Energy

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SUMMARY

The discussion centers on calculating the rotational speed required for a 20-kg flywheel with a radius of 0.34 m to store 1.3 x 109 J of energy, equivalent to the energy produced by gasoline for a 260-mile trip. The moment of inertia (I) is calculated using the formula I = 1/2 * m * r2, resulting in I = 1.156 kg·m2. The angular velocity (ω) is derived from the equation 1.3 x 109 = 0.5 * I * ω2, leading to an angular speed of approximately 47425.05 rad/s, which must be converted to revolutions per minute (rev/min).

PREREQUISITES
  • Understanding of rotational dynamics and moment of inertia
  • Familiarity with angular velocity and its units
  • Knowledge of energy conversion in mechanical systems
  • Basic algebra for solving equations
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  • Learn about the principles of rotational kinetic energy storage
  • Study the conversion between radians per second and revolutions per minute
  • Explore applications of flywheels in energy storage systems
  • Investigate the efficiency of flywheels compared to traditional batteries
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wallace13
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A flywheel is a solid disk that rotates about an axis that is perpendicular to the disk at its center. Rotating flywheels provide a means for storing energy in the form of rotational kinetic energy and are being considered as a possible alternative to batteries in electric cars. The gasoline burned in a 260-mile trip in a typical midsize car produces about 1.3 x 10 9 J of energy. How fast would a 20-kg flywheel with a radius of 0.34 m have to rotate in order to store this much energy? Give your answer in rev/min.



I= 1/2mr squared
J= 1/2 IW squared



.5*20*(.34*.34)
I=1.156
1.3 X 10 9 = .5 x 1.156 x W squared
W=47425.04558



My speed is obviously incorrect. I do not understand where the distance (260 mile trip) comes into play in this problem

Homework Statement

 
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wallace13 said:
.5*20*(.34*.34)
I=1.156
1.3 X 10 9 = .5 x 1.156 x W squared
W=47425.04558
OK. What are the units of ω? You'll need to convert from those standard units to the requested units of rev/min.
I do not understand where the distance (260 mile trip) comes into play in this problem
It doesn't. It's just there to provide some background information so the problem seems realistic.
 
okay i got it. thanks
 

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