Moment of Inertia: Non Uniform Rod

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SUMMARY

The discussion focuses on calculating the moment of inertia for a cantilever beam with two sections of variable thickness. The standard moment of inertia formula, I = π/4 * (Ro^4 - Ri^4), is referenced, but the user seeks to adapt it for a beam with discrete thickness variations. The proposed solution involves using I1 = π/64 * (D^4 - (D - T1)^4) and adjusting it based on the length ratio. The key takeaway is that moments of inertia are additive, allowing for the calculation of the total moment of inertia by summing the contributions from each section.

PREREQUISITES
  • Understanding of moment of inertia concepts
  • Familiarity with cantilever beam mechanics
  • Knowledge of geometric properties of shapes
  • Basic calculus for integration of variable thickness
NEXT STEPS
  • Research the derivation of moments of inertia for composite shapes
  • Learn about the application of the parallel axis theorem in beam analysis
  • Explore finite element analysis (FEA) tools for complex beam geometries
  • Study variable thickness beam design principles in structural engineering
USEFUL FOR

Mechanical engineers, structural engineers, and students studying beam mechanics who need to calculate moments of inertia for cantilever beams with varying thicknesses.

Andrew VanFossen
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Homework Statement


Hello,

I am looking to determine the moment of inertia for the cantilever beam pictured below. I want I to be a function of L1 and T1.

Known variables: L, D, P, t
Dependent variables: T2, L2
Design variables: T1, L1

rod.PNG


Homework Equations


L2 = L - L1
T2 = T1 - t

Standard Moment of Inertia: I = π/4 * (Ro^4 - Ri^4)
I am looking to modify the above equation to be include 2 sections of variable thickness

The Attempt at a Solution


I1 = π/64 * (D^4 - (D - T1)^4)
I = I1 * (1 - L1/L)^4

The above solution is valid for a linearly tapered beam, not a beam with 2 discrete sections. I have not been able to find any derived moments of inertia for the above shape. Any help would be greatly appreciated!
 
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Andrew VanFossen said:
I have not been able to find any derived moments of inertia for the above shape.
Moments of Inertia are additive. Just break it up into pieces of convenient shape, find the MoI of each (about the same axis) and add them up.
 

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