Moment of inertia of a metal plate about three points

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Homework Help Overview

The discussion revolves around calculating the moment of inertia of a modified metal plate, initially a square, after a quarter has been removed. The focus is on determining the moment of inertia about three specific points: the top left corner, the origin, and a point where the right-lowest corner used to be, with an emphasis on ranking these values.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the parallel axis theorem and the implications of the center of mass on the moment of inertia calculations. There are attempts to clarify the relationship between the distances of the points and their respective moments of inertia.

Discussion Status

Some participants have provided guidance on how to approach the problem by suggesting calculations for the moment of inertia before and after the square was cut off. Others have pointed out potential misunderstandings regarding the application of the parallel axis theorem and the importance of the center of mass.

Contextual Notes

There is an ongoing discussion about the correct interpretation of the parallel axis theorem and its application in this context, as well as the need for clarity on the center of mass of the modified plate.

Krushnaraj Pandya
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Homework Statement


Moment of inertia of a metal plate (center at origin) which was a square before 1/4th of it was cut off (4th quadrant), about three points a)- top leftmost corner in 2nd quadrant b)- origin and c) (where the right-lowest corner used to be in 4th quadrant) ranked in decreasing order

Homework Equations


I=Mr^2

The Attempt at a Solution


using my intuition, I figured the order is c<a<b, since more points are farther away from c, then a and then b- but according to parallel axis theorem moment of inertia at b and c should be same...i'm confused how to do this mathematically
 
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Krushnaraj Pandya said:
but according to parallel axis theorem moment of inertia at b and c should be same...
Can you explain this?

I have a feeling you meant to say “a and c should be the same”? If so, your mistake is that the parallel axis theorem must use the center of mass. The CoM is not at the origin.
 
Start by determining the moment of inertia of the plate before the square was cut off. Determine it for each of the three points. Then determine the moment of inertia of the plate that was cut off. Determine that for each of the three points. Now subtract. The moment of inertia of the plate after the square was cut off is the moment of the plate before the square was cut off, minus the moment of the square that was cut off.
 
Nathanael said:
Can you explain this?

I have a feeling you meant to say “a and c should be the same”? If so, your mistake is that the parallel axis theorem must use the center of mass. The CoM is not at the origin.
yes, that's what I meant. Thanks for pointing out my mistake
 
Gene Naden said:
Start by determining the moment of inertia of the plate before the square was cut off. Determine it for each of the three points. Then determine the moment of inertia of the plate that was cut off. Determine that for each of the three points. Now subtract. The moment of inertia of the plate after the square was cut off is the moment of the plate before the square was cut off, minus the moment of the square that was cut off.
Excellent! Thanks a lot
 
Moment of inertia is additive, so what Gene says is true. But, if we’re only asked to rank the three points in descending order, then we don’t need to do all that work.

Your intuition (and answer) is correct. The parallel axis theorem can be used to restate the problem as, “order a,b,c by their distance to the center of mass,” which is simpler.
 
Nathanael said:
Moment of inertia is additive, so what Gene says is true. But, if we’re only asked to rank the three points in descending order, then we don’t need to do all that work.

Your intuition (and answer) is correct. The parallel axis theorem can be used to restate the problem as, “order a,b,c by their distance to the center of mass,” which is simpler.
Certainly, I understand it much better now. Thank you.
 

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