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## Homework Statement

A stiff uniform wire of mass M

_{0}and length L

_{0}is cut, bent, and the parts soldered together so that it forms a circular wheel having four identical spokes coming out from the center. None of the wire is wasted, and you can neglect the mass of the solder.

What is the moment of inertia of this wheel about an axle through its center perpendicular to the plane of the wheel? Express your answer in terms of the given quantities.

## Homework Equations

I

_{rim}= MR

^{2}

I

_{spoke}= 1/3ML

^{2}

I

_{total}= I

_{rim}+ 4*I

_{spoke}

## The Attempt at a Solution

The length of one spoke, which should also be the radius of the rim, should be L

_{0}/(2[itex]\pi[/itex]+4)

I am unsure of the mass of one spoke, as well as the mass of the rim. Would the mass of one spoke be the same ratio? (M

_{spoke}= M

_{0}/(2[itex]\pi[/itex]+4)) ?

If so, then what would be the mass of the rim? I thought M

_{rim}= M

_{0}- 4*M

_{spoke}

therefore M

_{rim}= (M

_{0}*(1-4/(2[itex]\pi[/itex]+4))

but I am not getting it right when I submit it.