Moment of Inertia of a Wagon Wheel

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SUMMARY

The moment of inertia of a wagon wheel is calculated by considering both the rim and the spokes. The rim, with a mass of 1.36 kg and a radius of 0.300 m, contributes I = 1.36 * (0.300)^2. Each of the eight spokes, each with a mass of 0.270 kg and treated as thin rods, requires the use of the moment of inertia formula for a thin rod about one end. The total moment of inertia is the sum of the contributions from the rim and the spokes.

PREREQUISITES
  • Understanding of moment of inertia concepts
  • Familiarity with the formula for the moment of inertia of a thin rod
  • Basic knowledge of mass distribution in rigid bodies
  • Ability to perform calculations involving radius and mass
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  • Research the moment of inertia formulas for different shapes
  • Learn about the parallel axis theorem in rotational dynamics
  • Explore applications of moment of inertia in engineering design
  • Study the dynamics of rotating bodies and their stability
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Physics students, mechanical engineers, and anyone interested in the dynamics of rotating systems will benefit from this discussion.

Trojanof01
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A wagon wheel is constructed as shown in the figure. The radius of the wheel is 0.300 m, and the rim has mass 1.36kg . Each of the eight spokes, that lie along a diameter and are 0.300 m long, has mass 0.270kg .

What is the moment of inertia?


Wouldn't it just be the sum of the masses times the radius squared?

I = 1.36(.300)^2 + .8(.270(.300^2))
 
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Trojanof01 said:
Wouldn't it just be the sum of the masses times the radius squared?
For the rim, yes; for the spokes, no. The mass of the rim is all at a single distance from the axis; not so for the mass of the spokes. Hint: Look up (or figure out) the moment of inertia of a thin rod about one end. (Treat the spokes as thin rods.)
 
Oh! /smack That made that so much more simple. Thanks much.
 

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