Moment of inertia of an object with uneven distribution of weight

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The discussion centers on calculating the rotational kinetic energy of a can rolling down an inclined plane, specifically addressing the moment of inertia when mass is unevenly distributed. The equation I=mr^2 is typically applicable for objects with uniform mass distribution, raising questions about its validity when mass is added to one side of the can. It is clarified that the general formula for moment of inertia, I=∫r² dm, should be used to accurately account for the uneven mass distribution in this scenario. The suggestion is made to distribute the added mass in a way that simplifies the integral for easier calculation. Accurate calculations will depend on considering how the bluetag affects the overall mass distribution.
sungj25
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I'm doing an experiment and I have to calculate calculate rotational kinetic energy of this can rolling down an inclined plane.
According to the equation, Er=1/2Iw^2, I=mr^2, and w=v/r (no slipping effect) right?
but doesn't I=mr^2 apply only when the weight is evenly distributed throughout the axis?

In my experiment, I'm going to add mass only on one side of an empty cylindrical can (using bluetag). Will I be still able to calculate the inertia using this I=mr^2 equation?

thank you for reading!
 
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The general formula for calculating the moment of inertia of a body about an axis is:

I=\int r^{2} dm

where r represents the distance of the mass element from the rotational axis. If the distance from the axis is so large that the distribution of the mass becomes negligible, then the formula you mention (mr2) is applicable. (for example the moment of inertia of the Earth about the sun).

For your experiment you will need to use the general formula to account for the manner in which you distribute your bluetag. You might want to distribute the bluetag in a manner to simplify the integral.
 

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