The discussion revolves around calculating torque to determine string tension in a physics problem involving a mass placed on a board supported by strings. Participants are exploring the relationship between the position of the mass and the resulting tension in the strings.
There is an ongoing exploration of the implications of the calculated distance for the mass and how it relates to the stability of the strings. Some participants have provided guidance on interpreting the results and translating them into the required format, while others are questioning the assumptions made in the calculations.
Participants are working within the constraints of a homework assignment, which may limit the information available and the methods allowed for solving the problem. There is a focus on understanding the physical setup and the consequences of different placements of the mass on the board.
Doc Al said:
Doc Al said:Your work and diagram are perfectly correct. You just need to translate your answer into the form that they want. They asked for the fraction of the board, not the position of the mass.
Doc Al said:
Right. So how much of the board is "off limits" for the string not to break? (Consider both ends.)tweety1234 said:
doc al said:
Yes, viewed from side A. Now view from the other side.tweety1234 said:
Doc Al said:
That's right.tweety1234 said:
Yes. Analzying things form side A tells you that placing the mass between 6 and 8 meters from A will cause string B to break. A similar analysis applies from side B. That means 2 m on both ends of the board are off limits--a total of 4 m out of 8. What fraction is that?
Doc Al said:That's right.
Yes. Analzying things form side A tells you that placing the mass between 6 and 8 meters from A will cause string B to break. A similar analysis applies from side B. That means 2 m on both ends of the board are off limits--a total of 4 m out of 8. What fraction is that?