Momentum & Impulse: Find Average Force in Elastic Collision

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    Impulse Momentum
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Homework Help Overview

The problem involves an elastic collision between two identical locomotives, focusing on calculating the average force exerted on one of the locomotives during the collision. The context includes concepts of momentum and impulse.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of momentum before and after the collision, questioning which momentum to use for calculating the average force. There is an exploration of the change in momentum and its implications for the calculation.

Discussion Status

Some participants have provided guidance on using the change in momentum to find the average force, while others are clarifying the initial and final momentum values involved in the calculation. Multiple interpretations of the momentum usage are being explored.

Contextual Notes

There is a mention of the collision lasting for a specific duration and the assumption that one locomotive is initially stationary, which may influence the calculations being discussed.

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Homework Statement


A locomotive of mass 21x10^3kg traveling at 2.0m/s runs into an identical stationary locomotive.

If the collision is perfectly elastic and lasts for 1.5s, find the average force exerted on the stationary locomotive during the collision.


Homework Equations


Find momentum before and after the collision (m1v2 + m2v2 = m1v2 + m2v2)

Use impluse to find the average force (F = p/t)


The Attempt at a Solution


I found the momentum before and after the collision.

For the second part, I'm not sure which momentum to use. The final one?

Can someone tell me if I'm right?
 
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mizzy said:
Use impluse to find the average force (F = p/t)
That should be F = Δp/t.

For the second part, I'm not sure which momentum to use. The final one?
You need the change in momentum.
 
the change in momentum after the collision?
 
mizzy said:
the change in momentum after the collision?
Change = Final - Initial

I guess the initial momentum of the stationary locomotive was zero; so you're OK with using the final momentum. :smile:
 
Thanks :smile:
 

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