Momentum Lab Help: Calculate Friction, Coefficient & Work

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Homework Help Overview

The discussion revolves around a physics experiment involving momentum, specifically focusing on calculating friction, the coefficient of friction, and work done by friction after two mini-carts are pushed apart. The original poster has collected various data points, including acceleration, distance, time, initial and final velocities, mass, normal force, and momentum.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to relate the forces acting on the carts to their motion and questions whether acceleration should be considered negative. Participants discuss the role of friction as the only force acting on the carts post-push and explore how to calculate the coefficient of friction and work done.

Discussion Status

Participants are actively engaging with the original poster's calculations and reasoning. Some have provided guidance on the correct equations to use, while others have clarified concepts related to friction and momentum. There is an ongoing exploration of the relationships between the forces and the resulting motion of the carts.

Contextual Notes

There is mention of specific homework requirements, including the need to calculate various physical quantities based on experimental data. The original poster is also navigating potential misunderstandings about the definitions and implications of momentum in the context of the experiment.

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Homework Statement


The other day, I was asked to conduct an experiment involving momentum. Basically, I set two mini-carts bumper to bumper, and hit a switch that caused them to push away from each other and travel in opposite directions. We then had to repeat the experiment using different weights and such.

Anyway, after collecting the data, my physics teacher wants us to find the force of friction, coefficient of friction, and work done by friction. How do I approach these questions? I already know the carts’ Acceleration, Distance, Time, Initial Velocity, Final Velocity, Mass, Normal Force, and Momentum. Also, is acceleration supposed to be negative in these situations?

Homework Equations



Momentum = Mass * Velocity
Coefficient of Friction = Normal Force * Force of Frction
Friction = Force Applied from X Direction * (mass * acceleration)

The Attempt at a Solution



Fn - f = (mass x acceleration)
:18N - f = 1.8kg x -.106m/s^2 ?
::-f = -18
:::f = 18 N

Thanks for the help!
 
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No your calculation isn't correct. After the cart has been pushed, there is only one force acting on it. What do you think this is? This should answer your question about negative acceleration, and enable you to use Newton's second correctly.
 
cristo said:
No your calculation isn't correct. After the cart has been pushed, there is only one force acting on it. What do you think this is? This should answer your question about negative acceleration, and enable you to use Newton's second correctly.

Well, the only force acting on the carts after the push is Friction. I'm guessing since it's slowing the cart down, the force is negative - as it opposes forward progress. So, would friction be equal to (mass * -a)?
 
Correct. So, you now have the magnitude of friction. Can you calculate the coefficient and work done?
 
cristo said:
Correct. So, you now have the magnitude of friction. Can you calculate the coefficient and work done?

I believe so. All I have to do is plug the Force of Friction into the "Coefficient of Friction = Normal Force * Force of Friction, correct? :)
 
Well, the correct equation is force of friction=coefficient * normal force. But yes you just plus in the values you know.
 
Oh okay. Thanks for all the help, I really appreciate it!

Have a nice day. :-)
 
You're welcome!
 
Apparently, there is another question that asks, "What was the momentum of the system after collision?". What does my teacher mean when he says "momentum of the system"? Is it the average Momentum from both carts?
 
Last edited:
  • #10
Total momentum of the system will be the sum of the momenta of the two carts.
 
  • #11
Allrighty, thanks again!
 

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