How Does Elastic Collision Affect Particle Momentum?

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The discussion focuses on calculating the mass of an unknown particle involved in an elastic collision with a proton. The proton, with a mass of 1.67 x 10^-27 kg, initially moves at 6 Mm/s and rebounds at 3.6 Mm/s after the collision. The momentum conservation equation is applied: P1 + P2 = P1' + P2', leading to the equation 3.006 x 10^-20 kg(Mm/s) = 1.08216 x 10^-26 kg(Mm/s) + P2. The next step involves using the relationship of relative velocities in elastic collisions to determine the unknown particle's mass.

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Here's a question from my workbook that I can't seem to figure out.

A proton (mass = 1.6 x 10^27 kg) moves with a speed of 6 Mm/s. Upon colliding elastically with a stationary particle of unknown mass, the proton rebounds on its own path with a speed of 3.6 Mm/s. Find the mass of the unknown particle.

Let's start with what I know. I know that momentum = mass times velocity.
or p = mv

I also know that since it's elastic, it isn't losing any energy.

So I used the equation P1 + P2 = P1 + P2

(1.67 x 10^-27 kg)(6 Mm/s) + 0 = (1.67 x 10^-27 kg)(-3.6 Mm/s) + P2

I said 3.6 Mm/s was negative since it was in the opposite direction.

So from there I got:

3.006 x 10^-20 kg(Mm/s) = 1.08216 x 10^-26 kg(Mm/s) + P2

P2 = 1.923 x 10^-26

But, from there I'm not sure where to go. I'm trying to find the mass of this particle, but I need to know it's velocity. :frown: Any help or hints is appreciated.
 
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The relative velocities of the bodies before and after an elastic collision have a predictable relationship. You could use that to find the mass.

Dorothy
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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