(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A tennis ball of mass = 0.060 kg and speed = 26 m/s strikes a wall at a 45° angle and rebounds with the same speed at 45° .

2. Relevant equations

Δp = pfinal - pinitial

horizontal velocity = (26 m/s)cos 45°

There's a picture if you all care.

3. The attempt at a solution

pintial = mv

pintial = (0.060 kg)cos 45°

pinitial = 1.1028 kgm/s

pfinal = - pintial

I made this relationship because it is now going in the opposite direction.

pfinal = -1.1028 kgm/s

Δp = -1.1028 kgm/s - 1.1028 kgm/s = -2.2056 kgm/s

The answer is positive and I cannot understand why.

What is the direction of the impulse given to the ball?

A. Upward

B. Downward

C. Left

D. Right

I've eliminated B and C but I'm still unsure. The sine and cosine of forty-five degrees are the same.

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# Homework Help: Momentum of a Tennis Ball at an Angle

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