A cannon shoots a shell straight up. It reaches its maximum height, 875 feet, and splits into two pieces, one weighing 3 lb and the other 5 lb. The two pieces are observed to strike the ground simultaneously. The 5 lb piece hits the ground 1,659 feet away from the explosion (measured along the x axis). Find the magnitude of the velocity of the 5 lb piece jsut after the explosion. Work done before explosion = 8lb * 32 ft/s^2 * 875 ft = 224000 J work done before explosion = work done after explosion work done after explosion = work done by 3lb + work done by 5 lb = 224000 J work done by 3lb= 3lb * 32 ft/s^2 * 875 ft = 84000 J work done by 5 lb = 224000 - 84000 = 140000 J work = integral of force done work done by 5 lb = integral of force in x direction + integral of force done in y direction where do I go from here?