Momentum Operator: Comparing p_x and p

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    Momentum Operator
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Homework Help Overview

The discussion revolves around the definition of the momentum operator in quantum mechanics, specifically comparing different representations of the momentum operator \( p_x \) and \( p \) as found in various sources, including a textbook and other literature.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand the differences in definitions of the momentum operator and questions whether they represent the same concept. Some participants provide insights into the mathematical relationships between the different forms presented.

Discussion Status

Participants are exploring the nuances of the definitions and their implications. Some have provided clarifications regarding the sign conventions used in physics, and a reference has been shared for further details. There is an ongoing examination of the topic without a clear consensus yet.

Contextual Notes

The original poster expresses uncertainty about the definitions and their equivalence, indicating a potential gap in understanding the conventions used in different contexts.

hyddro
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This is not really a homework problem but rather a homework-related question.. When I came across my homework (and my textbook: Atkin's physical chemistry 9th Ed.), they defined the momentum operator as:

p_x = - ( [itex]\hbar[/itex] / i ) * d/dx...

but i have seen in other sources that they define it as p = ( [itex]\hbar[/itex] * i ) * d/dx...

they multiply i rather than divide and it is also positive.. i don't known if they represent the same or not, if so.. how can you convert one to the other? Thanks and sorry if this is a very silly question..
 
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We have

[tex]\frac{1}{i} = -i[/tex]
 
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Thanks! I know it was something easy and silly. Thanks again.
 

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