Momentum Problem - Is it correct?

  • Thread starter AnomalyCoder
  • Start date
  • Tags
    Momentum
In summary, the initial velocity of the 4kg cart is 56kgm/s and after colliding and coming to a complete stop, its velocity is 0. The momentum of the 4kg cart is transferred to the 8kg cart, causing it to move with a velocity of half the initial velocity of the 4kg cart, or 7kg/s. Momentum is conserved in this collision, resulting in the 8kg cart gaining momentum and moving with a velocity of 7kg/s after the collision.
  • #1
AnomalyCoder
29
0

Homework Statement


A 4kg traveling at 14m/s collides with a stationary 8kg cart. The collision causes the 4kg cart to completely stop, and sets the 8kg cart in motion. Determine the velocity of the 8kg cart after the collision.

Homework Equations


m1 = -m2
VFinal-VInitial = m

The Attempt at a Solution


Initially the velocity of the 4kg is 4kg*14m\s, or 56kgm/s.
After it halts completely, therefore a velocity of 0.
m1 = 0-56kgm\s.

Next the 8kg cart; initially it is at 0kg\s.
After it is 8kg*x.
(8x-0) = m2

Thus -56kgm\s = 8x;
x = -7kg/s.

m1 = -m2, therefore -7 becomes 7?

I'm not sure if this is correct. Any help, tips, and resources appreciated.
 
Physics news on Phys.org
  • #2
Your units are all over the place. But the general idea is correct. Momentum is conserved because there is no force acted on the system. Therefore, the momentum before the collision equals the momentum after the collision. Thus, since your original mass is 4 kg and it is traveling at 14 m/s, it's momentum is 14 * 4. This must be the same as the other object's momentum afterwards. Therefore, the magnitude of the second object's velocity is simply half of the first object's velocity.
 
  • #3
Total momentum before collision = total momentum after collision. There is no negative sign.
 
  • #4
rl.bhat said:
Total momentum before collision = total momentum after collision. There is no negative sign.

He has used the same concept but written it as:

momentum lost by one body = momentum gained by the other.
since there is "gained" at one place and "lost" at the other there is a negative sign.
 
  • #5


Your approach and equations are correct. However, there is a minor mistake in your calculation for the velocity of the 8kg cart after the collision. You have correctly found that the final velocity of the 4kg cart is 0, and the initial velocity of the 8kg cart is 0. So, using the equation VFinal-VInitial = m, we have:

VFinal - 0 = -56kgm/s
VFinal = -56kgm/s

This means that the 8kg cart will have a velocity of -56kgm/s after the collision. This is because the negative sign indicates that the 8kg cart is moving in the opposite direction to the 4kg cart. Therefore, the magnitude of the velocity is still 56kgm/s, but the direction is opposite.

Other than that minor mistake, your solution is correct. Well done!
 

1. Is the conservation of momentum always correct?

No, the conservation of momentum is only correct in isolated systems where there are no external forces acting on the system. In real-world situations, there may be external forces that can affect the momentum of an object.

2. How do you calculate momentum?

Momentum is calculated by multiplying an object's mass by its velocity. The formula for momentum is p = mv, where p is momentum, m is mass, and v is velocity. The SI unit for momentum is kilogram-meter per second (kg*m/s).

3. Can momentum be negative?

Yes, momentum can be negative. The sign of momentum indicates the direction of motion, so a negative momentum means the object is moving in the opposite direction of the chosen positive direction. For example, if you choose the positive direction to be to the right, an object moving to the left will have a negative momentum.

4. Does the mass of an object affect its momentum?

Yes, the mass of an object directly affects its momentum. A heavier object will have a greater momentum than a lighter object, assuming they are both moving at the same velocity.

5. How does momentum relate to force?

Momentum and force are related through Newton's second law of motion. The change in an object's momentum is equal to the net force acting on it, and this change is in the direction of the force. This can be expressed as F = mΔv/Δt, where F is force, m is mass, Δv is change in velocity, and Δt is change in time.

Similar threads

  • Introductory Physics Homework Help
2
Replies
40
Views
2K
  • Introductory Physics Homework Help
Replies
10
Views
2K
  • Introductory Physics Homework Help
Replies
6
Views
6K
  • Introductory Physics Homework Help
Replies
13
Views
5K
Replies
23
Views
463
  • Introductory Physics Homework Help
Replies
3
Views
4K
  • Introductory Physics Homework Help
Replies
5
Views
2K
  • Introductory Physics Homework Help
Replies
8
Views
2K
  • Introductory Physics Homework Help
Replies
10
Views
824
  • Introductory Physics Homework Help
Replies
11
Views
2K
Back
Top