For an obejcting in a state of rotation, the velocity is always tangential to the distance acceleration to the axis of rotation. From what I read, the momentum vector, p = mv, is always parallel. Would it then be right to state that the momentum vector, p, is nothing more than a scalar product of m and v? In other words, the momentum vecotr is "superimposed" onto the velocity vector and therefore parallel. In looking at this from the cross product, v x vm (where both v are vector), the product = 0 because the angle between them is zero. Sin(0°) = 0. Am I looking at this from the right angle or is there a better way to look at it?