For an obejcting in a state of rotation, the velocity is always tangential to the distance acceleration to the axis of rotation.(adsbygoogle = window.adsbygoogle || []).push({});

From what I read, the momentum vector, p = mv, is always parallel.

Would it then be right to state that the momentum vector, p, is nothing more than a scalar product of m and v?

In other words, the momentum vecotr is "superimposed" onto the velocity vector and therefore parallel.

In looking at this from the cross product, v x vm (where both v are vector), the product = 0 because the angle between them is zero. Sin(0°) = 0.

Am I looking at this from the right angle or is there a better way to look at it?

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# Momentum vector always parallel to velocity

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