Monopole and Dipole moments

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SUMMARY

The discussion focuses on calculating the monopole and dipole moments for a dielectric sphere with a surface charge density defined as sigma(theta) = sigma(0)cos(theta). The monopole moment is determined by integrating the surface charge density over the sphere's surface, yielding the total charge. For the dipole moment, the calculation involves integrating Rσ(θ) over the sphere's surface, where R represents the sphere's radius. The participants confirm the use of multipole expansion formulas in spherical coordinates for these calculations.

PREREQUISITES
  • Understanding of surface charge density and its mathematical representation
  • Familiarity with monopole and dipole moment calculations
  • Knowledge of multipole expansion in electrostatics
  • Proficiency in performing surface integrals in spherical coordinates
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  • Research the mathematical derivation of monopole and dipole moments for arbitrary charge distributions
  • Study the application of multipole expansion in electrostatics
  • Explore advanced techniques for surface integrals in spherical coordinates
  • Learn about the physical implications of monopole and dipole moments in electromagnetic theory
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Students and professionals in physics, particularly those specializing in electromagnetism, electrostatics, and mathematical physics, will benefit from this discussion.

babtridge
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I'm having a lot of difficulty calculating the monopole and dipole moments for a dielectric sphere with surface charge of the form,

sigma(theta)=sigma(0)cos(theta)

If surface charge wasn't present and it was just a point charge I would be OK but I need a few pointers on how to do it with the above surface charge density.

Thanks in advance guys...
 
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What have you tried so far? For arbitary charge densities the moments are

\int {\rho(\vec{r'}) dV'}

and

\int {\vec{r'}\rho(\vec{r'}) dV'}

The monopole moment is just the total charge on the surface. So integrate your surface charge density over the surface of the sphere. For the dipole moment I'm not that sure but I think you have to do the same for R\sigma(\theta) where R is the radius of the sphere. Don't quote me on this though.

edit: change the second intergation over all components of the r vector over the sphere's surface. that would make much more sense than what I previously wrote.
 
Last edited:
Cheers mate,
I was using the multipole expansion formula of phi(r) in spherical polars.
My working matches what you have said so thanks for confirming that!

:smile:
 

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