Monster E&M Question (Coulomb's Law, Electric Potential, Kinematics)

Click For Summary
SUMMARY

The discussion centers on calculating the forces, potential energy, accelerations, and final velocities of a proton and an alpha particle using Coulomb's Law and kinetic energy equations. The force between the particles is determined to be 51.2 N, with a potential energy of 1.5e-13 J. The initial accelerations are calculated as 3e28 m/s² for the proton and 8e27 m/s² for the alpha particle. The final velocities, after converting potential energy into kinetic energy, are found to be 1.34e7 m/s for the proton and 6.72e6 m/s for the alpha particle.

PREREQUISITES
  • Coulomb's Law for electrostatic force calculations
  • Understanding of potential energy in electric fields
  • Basic kinematics and acceleration equations
  • Knowledge of kinetic energy and its relation to velocity
NEXT STEPS
  • Study the derivation and applications of Coulomb's Law in different contexts
  • Explore the concept of electric potential energy and its calculations
  • Learn about integrating acceleration functions to find velocity over time
  • Investigate the conservation of energy principles in particle physics
USEFUL FOR

Students in physics, particularly those studying electromagnetism and kinematics, as well as educators looking for problem-solving techniques in particle interactions.

kosovo dave
Gold Member
Messages
34
Reaction score
0

Homework Statement


A proton (charge +1e and mass 1.67e-27kg) and an alpha particle (charge +2e and mass 6.64e-27kg) are placed 3 fm (1 fm=10e-15m) apart.
a)what is the force on each particle
B)what is the potential energy of the system?
c)what is the acceleration of each particle at the beginning?
d)after a long time the two particles are far apart. what is the speed of each particle at this point?

Homework Equations



F = ( q_1 q_2) / 4 π ε_0 r^2 = (k q_1 q_2) / r^2
U = q v = ( q_1 q_2) / 4 π ε_0 r
K E = 1 / 2 m v^2
F = E q = m a

The Attempt at a Solution


a) Using Coulomb's Law, I found the force to be 51.2 N.
b) substituting my values into the second equation above, I got that the potential energy of the system is 1.5e-13 J.
c)Using the fourth equation above I found the accelerations. For the proton I got 3e28 m/s^2. For the alpha particle I got 8e27 m/s^2.
d) This part got a little tough. Realizing that the acceleration decreases as the particles move apart, I tried to integrate their acceleration from their initial separation out to infinity, but this quickly proved to be tedious/confusing. Looking at it again, I realized that as the particles move towards infinity all of the potential energy will be converted into kinetic energy. So I solved equation 3, substituting my answer from b) in for the kinetic energy and the mass of each particle. I found the velocity of the proton to be 1.34e7 m/s and the velocity for the alpha particle to be 6.72e6 m/s.

Did I do this correctly? This question is from an old test my prof gave us to study (I don't have the solution) and I have no intuition for how quickly these types of particles should be moving.
 
Physics news on Phys.org
Yes.The procedure you did is correct.
 
Thanks! If I wanted to continue on my initial path of integrating (no pun intended) the acceleration to get the final velocity, could somebody show how that would work?
 
What the supposed pun supposed to be?
 
path of integrating = path integral. not a good one, but gimme a break -- I've been studying all day.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
11
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
4
Views
1K
Replies
1
Views
1K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 1 ·
Replies
1
Views
6K
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
692