More integration by subsitution

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The discussion revolves around the integration of the function tan^4(3x)sec^2(3x)dx. The user successfully applied substitution by letting u = tan(3x), leading to the integral expressed as (1/3)∫u^4du. After integrating, they found the result to be (tan^5(3x)/15) + C. The user sought confirmation on the correctness of their differentiation, and received positive feedback affirming their solution. This exchange highlights the importance of verification in calculus problems.
mbrmbrg
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I (now) know that I can check the following by differentiating my answer, but I don't trust my differentiation.

Problem is as follows:

\int\tan^4{3x}\sec^2{3x}dx
I assigned u=tan(3x), du=3sec^2(3x) and got that integral in terms of u:
\frac{1}{3}\int u^4du
=\frac{1}{3}\times\frac{u^5}{5}+C
=\frac{\tan^5(3x)}{15}+C

I think that differentiates into what's in the original integral, but as I haven't differentiated anything that looks like that for a while now, I'd appreciate some feedback.

Thanks!
 
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thats correct
 
Thank you very much.
 
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