mbrmbrg
- 485
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I (now) know that I can check the following by differentiating my answer, but I don't trust my differentiation.
Problem is as follows:
\int\tan^4{3x}\sec^2{3x}dx
I assigned u=tan(3x), du=3sec^2(3x) and got that integral in terms of u:
\frac{1}{3}\int u^4du
=\frac{1}{3}\times\frac{u^5}{5}+C
=\frac{\tan^5(3x)}{15}+C
I think that differentiates into what's in the original integral, but as I haven't differentiated anything that looks like that for a while now, I'd appreciate some feedback.
Thanks!
Problem is as follows:
\int\tan^4{3x}\sec^2{3x}dx
I assigned u=tan(3x), du=3sec^2(3x) and got that integral in terms of u:
\frac{1}{3}\int u^4du
=\frac{1}{3}\times\frac{u^5}{5}+C
=\frac{\tan^5(3x)}{15}+C
I think that differentiates into what's in the original integral, but as I haven't differentiated anything that looks like that for a while now, I'd appreciate some feedback.
Thanks!