Mossbauer Effect how does it work?

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SUMMARY

The Mossbauer effect involves the recoil-free emission and absorption of gamma rays by atoms in a solid. The discussion clarifies that the entire crystal lattice absorbs the recoil, not just the emitting atom. The emission occurs in approximately 1E-22 seconds, while the interaction time with neighboring atoms is significantly longer, at 3E-19 seconds for the nearest neighbor. The explanation provided indicates that the emitting atom exists within a preexisting electrostatic potential, allowing for local interactions that facilitate the recoil transfer without violating the speed of light.

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edpell
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I know what the Mossbauer effect is. I know the crystal as a whole accepts the recoil not just the atom emitting the gamma ray. But the gamma emission is a fast nuclear event say 1E-22 seconds. The distance, in terms of time, to the nearest neighbor atom is 3E-19 seconds not to mention the distance, in terms of time, to an atom 100 unit cells away is 3E-17 seconds. It would seem the momentum would have to be transferred faster than the speed of light. How does this work?
 
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Well, I think the explanation is that the emitting atom sits in a preexisting electrostatic potential, and its recoil pushes against that, as a local interaction. It's true the recoil eventually has to be imparted to the other atoms through a readjustment of the electrostatic field, but this does not have to take place at the moment the gamma ray is emitted.
 

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