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Motion in Two and Three Dimensions and airplane

  1. Oct 21, 2009 #1
    The airplane shown is in level flight at an altitude of 0.50 km and a speed
    of 150 km/h. At what distance d should it release a heavy bomb to hit the
    target X?

    -I tried using x-x0=(v0)(cos(theta))t; and then solving for t with another equation but that does not give me the correct answer when I solve for x. Any suggestions?
     
  2. jcsd
  3. Oct 21, 2009 #2
    Assume it isn't moving for a second. h=500m=0.5*g*t^2 => t=sqrt(2*500m/(10m/s^2)). So it will be in the air for this long. Now assume it is moving along the x-axis for this period of time, t. The distance it will travel will simply be t*(horizontal speed). So if it is moving at 2.5km/s, the distance d will be (2.5km/s)*sqrt(2*500m/(10m/s^2)).

    Does this help?
     
  4. Oct 21, 2009 #3
    No I actually got that answer through a different method, however, the correct answer is 417 m.
     
  5. Oct 21, 2009 #4
    I'm getting the correct answer to be 414.1m, and that is using what I explained earlier. Except I converted units wrong because I'm tired. :) 150km/h = 41m/s

    d=(41m/s)*sqrt(2*500m/(9.8m/s^2))=414m. This is definitely correct.
     
  6. Oct 21, 2009 #5
    150km/h=41.6666667m/s
    ==>
    d=(41.6666667m/s)*sqrt(2*500m/(9.8m/s^2))=417m

    Thar's your 417m.
     
  7. Oct 21, 2009 #6
    Wow your right
    I also converted units wrong
    this problem was really annoying,
    thanks for the help!
     
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