Motion in two dimension problem. Range and Height.

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A rocket is launched at 30.0 m/s at a 40-degree angle, prompting a discussion on calculating its maximum height, time in the air, and horizontal distance traveled. The problem involves breaking down the motion into vertical and horizontal components but restricts the use of direct formulas for range and height. Initially, the user struggled to find the time and final position despite using kinematic equations. Ultimately, the user resolved the problem independently, indicating a successful understanding of the concepts involved. The discussion highlights the importance of analyzing projectile motion in two dimensions.
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Homework Statement


A rocket is launched from level ground with a speed of 30.0 m/s at an angle of 40 degrees above the horizontal. Find:

a) Maximum height reached by the rocket.
b) The time rocket is in the air.
c) the horizontal distance where the rocket lands.


Homework Equations


V= Vo + at
V^2 = Vo^2 + 2a(X-Xo)
X= Xo +Vo(t) + (1/2)at^2

The Attempt at a Solution



Divided the entire motion into two phases 1st and 2nd, Got x and y components of everything. Can't seem to find the time and final position anyway. I am not allowed to use the direct formula for Range and Height.
Help please!
 
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You'll have to show some of your work so that we'll know where to help. What are your "phases"?
 
Well I meant the two different phases for first and second half part of its motion.

Never mind I figured out how to solve this problem.
Thanks anyway.
 

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