Motion of a particle in a verticle ring.

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    Motion Particle Ring
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Discussion Overview

The discussion revolves around the motion of a particle in a vertical ring, specifically focusing on the conditions under which the particle loses contact with the ring. Participants explore both intuitive and mathematical approaches to understanding this phenomenon, including the forces involved and the energy transformations at play.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant suggests that the particle loses contact due to its kinetic energy becoming zero as it converts to potential energy, questioning the mathematical proof for this assertion.
  • Another participant emphasizes the necessity of centripetal force for circular motion and questions the sufficiency of the forces acting on the particle, indicating that the conditions for losing contact may vary.
  • A participant identifies the centripetal force as the sum of the normal reaction force and the radial component of the weight, raising the question of which force's inadequacy leads to the loss of contact.
  • One participant proposes considering an extreme case where the particle breaks contact at the top of the ring, suggesting that this can help determine the minimum centripetal force required and extrapolate to other positions on the ring.
  • Another participant recommends drawing a free body diagram (FBD) and resolving forces to find the angle at which contact is lost, linking this to the conservation of energy principle.

Areas of Agreement / Disagreement

Participants express differing views on the conditions under which the particle loses contact with the ring, with no consensus reached on a definitive mathematical approach or the sufficiency of the forces involved.

Contextual Notes

There are unresolved assumptions regarding the specific conditions of motion and the definitions of forces involved, as well as the mathematical steps necessary to derive the required expressions for centripetal force.

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See attachment

the green spot shows the initial position of a particle
the blue spot shows the position at which the particle loses contact with the ring.

Intuitively one can easily deduce that the particle would indeed loose contact with the ring.

Is there a way to prove this mathematically ?

What exactly causes the particle to loose contact ?
Is it because its Kinetic energy becomes Zero (ie all of it has been converted to P.E)
 

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For the particle to undergo circular motion. it must undergo a centripetal force(what is the centripetal force in this case?) and if the force is not large enough it would break contact. So the statement that it would break contact anyway can be wrong regarding the different situations. So what we need to do now is to find the mathematical expression for this force then equate it with the expression of centripetal force.
 
The centripetal force in this case is the sum of two forces :

R (normal reaction from the surface of the ring)
W(the radial component of the weight )

Now, which force when not large enuf would cause the particle to stop the circular motion ?
 
Sorry for my English as I am taught in my native language.
Yes here the centripetal force is the resultant force of the two. But let's consider an extreme case that the particle breaks contact just at the top of the ring. Then what is the minimum centripetal force required? Using the equation we can calculate the minimum velocity required at that point. And it would be easy to extrapolate it to the situation when the particle breaks loose at any given point.
 
Dude if u draw the fbd of the particle at some general theta with the vertical/horizontal(whichever u prefer); try equating the the normal contact force component to zero AND resolving the component of mg along the radius of the circle, that component will provide the centripetal force at that point... If u r interested to find theta then use W(all) = change in KE
 

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