Motion Problem, Find Average Speed

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Homework Help Overview

The problem involves calculating the average speed of a return trip where the driver travels different speeds for equal distances and equal times. The subject area includes concepts of motion, specifically average speed and distance-time relationships.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to find time and distance relationships, with one suggesting a sketch to visualize the problem. There are attempts to set up equations based on the distances traveled at different speeds, and questions arise regarding the clarity of the steps taken in the calculations.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the relationship between speed, time, and distance, but there is no explicit consensus on the approach to take.

Contextual Notes

Participants are working under the constraints of the problem statement, which specifies the distances and speeds but does not provide explicit details on how to calculate the total time for the return trip.

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Homework Statement


Julie drives 100mi to Grandmother's house. On the way to Granmothers, Julie drives half the distance at 40mph and half the distance at 60mph. On the returntrip, she drives half the time at 40mph and half at 60mph.

What is her average speed on the return trip?

Homework Equations



v = v[0] + a dt
s[f] = s[0] + v[0] dt + 1/2 a dt^2

The Attempt at a Solution


I need to find the time first I think and then do .5*40t + .5*60t but I'm not sure how to find t
 
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You know speed, time and distance - nobody mentioned acceleration so you only need s = vt.
Draw a sketch of the various distances, speeds and times - it will help you understand what you are trying to find.
As a general tip - don't hit the equations until you know what you are trying to find!
 
s1 + s2 = 100

s1 = 1/2 * 40 t
s2 = 1/2 * 60 t

s1 = 100-s2




100 - s2 = 1/2 *40 t
s2 = 1/2 * 60 t


s2 = - 1/2 *40 t + 100
s2 = 1/2 * 60 t


-20t + 100 = 30t

10t = 100
t=10


(5*40 + 5*60 ) /10
(200+300)/10 = 50 mph

So basically like this?
 
Was confused by your work... can you describe your steps. You need to find the total time taken. Average speed = total distance/total time = 200/total time.
 

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