Motion with Constant Acceleration problem

In summary, the minimum runway length that will serve for a large, fully loaded passenger jet is 0.5 miles, using the hint of solving for the distance using ratios with the equations for the small and large planes.
  • #1
zerofaisal33
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Homework Statement


A smaller propeller airplane can comfortably achieve a high enough speed to take off on a runway that is 1/4 mile long. A large, fully loaded passenger jet has about the same acceleration from rest, but needs to achieve twice the speed to take off. What is the minimum runway length that will serve?

Hint: you can solve this problem using ratios without having any additional information.


Homework Equations



I used Vf^2=Vi^2 + 2a(x)

The Attempt at a Solution



Vf^2=Vi^2 + 2a(x)
Vi=0
Vf^2 = 2a(.25)
.25 = Vf^2/2a

now how do i solve for the larger plane?
 
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  • #2
zerofaisal33 said:

Homework Statement


A smaller propeller airplane can comfortably achieve a high enough speed to take off on a runway that is 1/4 mile long. A large, fully loaded passenger jet has about the same acceleration from rest, but needs to achieve twice the speed to take off. What is the minimum runway length that will serve?

Hint: you can solve this problem using ratios without having any additional information.


Homework Equations



I used Vf^2=Vi^2 + 2a(x)

The Attempt at a Solution



Vf^2=Vi^2 + 2a(x)
Vi=0
Vf^2 = 2a(.25)
.25 = Vf^2/2a

now how do i solve for the larger plane?

Welcome to the PF.

Be sure to carry units along in your equations as you work. It helps to avoid mistakes in unit conversions, and helps to make the equations clearer. It took me a beat or two to figure out that the 0.25 was in miles... :smile:

Now, you have an equation for the motion of the small plane, with its final velocity Vf and the distance it takes to take off (0.25 miles). The larger plane requires twice the final velocity to take off, but has the same acceleration. Write a similar equation for the large plane with the distance as a variable, and use the hint from the problem about taking ratios to solve for the unknown...
 

FAQ: Motion with Constant Acceleration problem

1. What is the equation used to calculate motion with constant acceleration?

The equation used to calculate motion with constant acceleration is x = x0 + v0t + 1/2at2, where x is the final position, x0 is the initial position, v0 is the initial velocity, t is the time, and a is the constant acceleration.

2. How does velocity change in motion with constant acceleration?

In motion with constant acceleration, velocity changes at a constant rate. This means that the velocity increases or decreases by the same amount in each unit of time.

3. Is the acceleration of an object always constant in motion with constant acceleration?

Yes, the acceleration of an object is always constant in motion with constant acceleration. This means that the acceleration does not change over time and is the same at every point during the motion.

4. What is the difference between average acceleration and instantaneous acceleration?

Average acceleration is the change in velocity over a period of time, while instantaneous acceleration is the acceleration at a specific moment in time. Average acceleration can be calculated using the equation a = (vf - vi) / t, while instantaneous acceleration is calculated using the derivative of the velocity function.

5. How can motion with constant acceleration be represented graphically?

In motion with constant acceleration, the position-time graph is a parabola, the velocity-time graph is a straight line, and the acceleration-time graph is a horizontal line. This is because the velocity changes at a constant rate, resulting in a linear relationship, while the position changes at a non-constant rate, resulting in a parabolic relationship.

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