Mountain Climbing: Solving Uneven Tensions in Rope

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To solve for the tensions in the rope while the climber rests between two cliffs, the vertical components of the tensions must equal the climber's weight of 596 N. The left tension makes a 65-degree angle, while the right tension makes an 80-degree angle with the horizontal. By resolving the tension vectors into their horizontal and vertical components, the equations can be set up to find the individual tensions. The horizontal components of both tensions must be equal, while the sum of the vertical components must match the climber's weight. This approach allows for calculating the tensions on both sides of the rope accurately.
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A mountain climber, in the process of crossing between two cliffs by a rope, pauses to rest. She weighs 596 N. As the drawing shows, she is closer to the left cliff than to the right cliff, with the result that the tensions in the left and right sides of the rope are not the same. Find the tensions in the rope (a) to the left and (b) to the right of the mountain cliff

The shape of thislooks like a "Y" but with uneven tension. the left tention is 65degrees and the right tension is 80degrees.

how can i solve for the 2 tensions?
 
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resolve the two tension vectors into horizontal and vertical components. The sum of the two vertical tension force components must equal the climbers weight force. The horizontal components must be equal to one another.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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