Newton's Laws: Force of Tension

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SUMMARY

The discussion focuses on calculating the tensions in the ropes supporting a mountain climber weighing 600 N, positioned between two cliffs. The climber's position results in unequal tensions on either side of the rope. To solve for the tensions, one must apply the principles of equilibrium, where the sum of vertical forces equals the weight of the climber, and the horizontal components of tension cancel each other out. This leads to two equations with two unknowns, allowing for the determination of the tensions in both segments of the rope.

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  • Familiarity with basic algebra for solving equations
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mcode
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Homework Statement



A mountain climber, in the process of crossing between two cliffs by a rope, pauses to rest. She weighs 600 N. As the drawing shows, she is closer to the left cliff than to the right cliff, with the result that the tensions in the left and right sides of the rope are not the same. Find the tensions in the rope (a) to the left and (b) to the right of the mountain climber.

http://www.pitt.edu/~mis98/ch04p_102.gif

Homework Equations



Net Force = Mass * Acceleration

The Attempt at a Solution



I'm not really sure how the force of tension works. If it was one rope I could assume that all the tension was on that, but with the two ropes I'm not sure how to figure out how much each rope is holding. I attempted to decompose the force of tension but then didn't know how to find the components. I'm really lost on this problem and any help would be greatly appreciated.
 
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mcode said:

Homework Statement



A mountain climber, in the process of crossing between two cliffs by a rope, pauses to rest. She weighs 600 N. As the drawing shows, she is closer to the left cliff than to the right cliff, with the result that the tensions in the left and right sides of the rope are not the same. Find the tensions in the rope (a) to the left and (b) to the right of the mountain climber.

http://www.pitt.edu/~mis98/ch04p_102.gif


Homework Equations



Net Force = Mass * Acceleration


The Attempt at a Solution



I'm not really sure how the force of tension works. If it was one rope I could assume that all the tension was on that, but with the two ropes I'm not sure how to figure out how much each rope is holding. I attempted to decompose the force of tension but then didn't know how to find the components. I'm really lost on this problem and any help would be greatly appreciated.
The woman is in equilibrium. No acceleration in x direction and no acceleration in y direction.
In both the ropes, tension will be along the 2 segments of the ropes. The angles at which the tensions work are given. The y components of tensions will balance the weight of the woman. and the x components will cancel out each other. Thus giving you 2 equations with two variables(Tensions in each segment). Solve it to get your answer.
 
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