Mountain Climbing: Solving Uneven Tensions in Rope

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SUMMARY

The discussion focuses on calculating the tensions in a rope used by a mountain climber weighing 596 N, positioned between two cliffs. The left tension forms a 65-degree angle, while the right tension forms an 80-degree angle with the horizontal. To find the tensions, participants recommend resolving the tension vectors into their horizontal and vertical components. The sum of the vertical components must equal the climber's weight, and the horizontal components must be equal to each other.

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  • Understanding of vector resolution in physics
  • Knowledge of trigonometric functions (sine and cosine)
  • Familiarity with equilibrium conditions in mechanics
  • Basic principles of tension in ropes
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This discussion is beneficial for physics students, mountain climbing enthusiasts, and anyone interested in understanding the mechanics of tension in climbing scenarios.

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A mountain climber, in the process of crossing between two cliffs by a rope, pauses to rest. She weighs 596 N. As the drawing shows, she is closer to the left cliff than to the right cliff, with the result that the tensions in the left and right sides of the rope are not the same. Find the tensions in the rope (a) to the left and (b) to the right of the mountain cliff

The shape of thislooks like a "Y" but with uneven tension. the left tention is 65degrees and the right tension is 80degrees.

how can i solve for the 2 tensions?
 
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resolve the two tension vectors into horizontal and vertical components. The sum of the two vertical tension force components must equal the climbers weight force. The horizontal components must be equal to one another.
 

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