# Moving down on a frictionless plane

1. Oct 14, 2008

### lacar213

1. The problem statement, all variables and given/known data
A shipping container is hauled up a roller ramp that is effectively frictionless at a constant speed of 2.10 m/s by a 2250 N force that is parallel to the ramp. If the ramp is at a 24.7° incline, what is the container's mass?

2. Relevant equations
Fx = mg sin(theta)
F = ma
A = Fx / m

3. The attempt at a solution
I tried the equations above but I'm unsure if I'm doing this correctly ...
2250/9.8 = 229.592
229.592sin(24.7)=95.9389
2250/95.9389=23.4524 kg

2. Oct 14, 2008

### Epsillon

Yes I think you are doing it correctly.

Since it is at a constant speed that means no acceleration hence no Fnet (N2)

So the force that is pushing it up should be equal the the x component of gravity.

Fgx=Fapplied

mgsin(theta)=Fapplied

3. Oct 14, 2008

### lacar213

these problems are on the Kinematic Books website - that answer ended up being incorrect - it doesn't tell you what the correct answer is

I'm not sure what I did wrong ... I tried that problem 3 times

4. Oct 14, 2008

### lacar213

these problems are on the Kinematic Books website - that answer ended up being incorrect - it doesn't tell you what the correct answer is

I'm not sure what I did wrong ... I tried that problem 3 times