Multiplying a matrix by its transpose

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Multiplying a matrix by its transpose is possible when the dimensions align correctly; a 3x2 matrix can be multiplied by a 2x3 transpose, resulting in a 3x3 matrix. The key condition for matrix multiplication is that the number of columns in the first matrix must equal the number of rows in the second matrix. The resulting matrix from this multiplication will have a rank of at most 2. Conversely, multiplying a 2x3 matrix by a 3x2 transpose yields a 2x2 matrix, also with a maximum rank of 2. Understanding these properties is essential for matrix operations in linear algebra.
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I don't see how you multiply a matrix by its transpose. If a matrix is 3 x 2 then its transpose is 2 x 3. I thought you couldn't multiply matrices unless they have the same rows and columns.
 
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For matrices to be multiplied, the condition is that the number of columns of the first matrix should be equal to the number of rows of the other matrix.
 


Nope, if a matrix A is n x m and B is m x l then AB is defined

If you do the same procedure of matric multiplication you'll see that multiplying a 3 x 2 and a 2 x 3 matrix gives you a 3 x 3 matrix of rank at most 2
If you multiply 2 x 3 by 3 x 2 you'll get a 2 x 2 matrix with rank, also (and obviously), at most 2

In terms of components if A = BC, where B is n x m and C is m x l, then

A_{i,k} = \sum_{j=1}^m B_{i,j} C_{j,k}
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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