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Is the wavefunction for x≤0 , ψ(x) = sinkx - acoskx equivalent to ψ(x) = -sinkx - acoskx where a is a constant ?

Thanks

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- #1

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Is the wavefunction for x≤0 , ψ(x) = sinkx - acoskx equivalent to ψ(x) = -sinkx - acoskx where a is a constant ?

Thanks

- #2

mfb

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No, and you didn't multiply ψ by a constant number to get the second expression.

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How to multiply wavefunction with a constant ? Could anyone please tell...thanks

- #4

mfb

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Write cψ instead of ψ. There, you multiplied ψ by a constant c.

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Thank you could you give an example? Thanks

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mfb

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| u > + | v >

1. a ( | u > + | v > ) where a is any number ( real or complex)

2. | u > + ( a | v > )

3 . e

4. | u > + ( e

- #8

mfb

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My confusion arises because I have come across the following statement " multiplying a wavefunction by a constant number or a phase doesn't change the wavefunction"

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Where did you come across this statement? Can you give a specific reference?I have come across the following statement " multiplying a wavefunction by a constant number or a phase doesn't change the wavefunction"

- #11

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| A > ≅ 2 | A > ≅ i | A > ≅ - | A > where ≅ represents physical equivalence "

- #12

mfb

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It leads to the same predictions for observable events if you take care of normalization.

- #13

Khashishi

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Perhaps you meant: ψ(x) = sinkx - acoskx equivalent to ψ(x) = -sinkx + acoskxIs the wavefunction for x≤0 , ψ(x) = sinkx - acoskx equivalent to ψ(x) = -sinkx - acoskx where a is a constant ?

(negative negative = plus)

If you change the overall scaling and phase of everything in the whole system equally, it makes no difference to the system. But if you change the phase of one wavefunction with respect to another wavefunction, this will change the system.

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