Multiplying Christoffel Symbols w/o Overloading Indices

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SUMMARY

The discussion focuses on the multiplication of Christoffel symbols, specifically the expression \(\Gamma^a_{vc}\Gamma^d_{ab}\). The user seeks guidance on performing this multiplication without overloading indices, proposing to sum over "a" first. The resulting expression involves a total of 16 products, with the initial four products detailed as \(\Gamma^1_{vc}\Gamma^c_{1b}\), which includes terms like \(\Gamma^1_{v1}\Gamma^2_{1b}\) through \(\Gamma^1_{v4}\Gamma^4_{1b}\). This method ensures clarity in the multiplication process by treating each index distinctly.

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  • Familiarity with tensor notation and index manipulation
  • Knowledge of summation conventions in mathematical expressions
  • Basic grasp of the properties of symmetric and antisymmetric tensors
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This discussion is beneficial for mathematicians, physicists, and students specializing in differential geometry or general relativity, particularly those working with tensor calculus and Christoffel symbols.

space-time
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This expression:

[itex]\Gamma[/itex]avc[itex]\Gamma[/itex]cab

Can someone please show me how to multiply the two Christoffel symbol formulas for these Christoffel symbols without overloading any indices?
 
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I would do this as two separate sums. If you sum over "a" first, you get [tex]\Gamma^a_{vc}\Gamma^d_{ab}= \Gamma^1_{vc}\Gamma^c_{1b}+ \Gamma^2_{vc}\Gamma^c_{2b}+ \Gamma^3_{vc}\Gamma^c_{ab}+ \Gamma^4_{vc}\Gamma^c_{4b}[/tex]

Now, in each of those replace c with 1, 2, 3, and 4. There will be a sum of 16 such products. The first four are [tex]\Gamma^1_{vc}\Gamma^c_{1b}= \Gamma^1_{v1}\Gamma^2_{1b}+ \Gamma^1_{v2}\Gamma^2_{1b}+ \Gamma^1_{v3}\Gamma^3_{1b}+ \Gamma^1_{v4}\Gamma^4_{1b}[/tex].
 

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