Multipole Expansion of a Thin Rod: How to Derive the Potential?

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SUMMARY

The discussion centers on deriving the potential of a uniformly charged thin rod along the z-axis, specifically for points far from the rod (r >> L). The potential is expressed as V(r, θ) = (2Lλ/4πε0)(1/L)[1 + 1/3(L/2r)²P2(cos θ) + 1/3(L/2r)⁴P4(cos θ) + ...]. Initial attempts to solve the problem using cylindrical coordinates were unsuccessful, leading to the use of Cartesian coordinates for integration. The user encountered an algebraic discrepancy in the final expression, prompting questions about the validity of their assumptions regarding θ.

PREREQUISITES
  • Understanding of electrostatics and electric potential
  • Familiarity with Legendre polynomials and their applications
  • Proficiency in calculus, particularly volume integrals
  • Knowledge of coordinate systems, specifically cylindrical and Cartesian coordinates
NEXT STEPS
  • Review the derivation of electric potential from charge distributions
  • Study the properties and applications of Legendre polynomials in physics
  • Practice solving integrals in both cylindrical and Cartesian coordinates
  • Explore the implications of multipole expansions in electrostatics
USEFUL FOR

This discussion is beneficial for physics students, particularly those studying electrostatics, as well as educators and researchers interested in charge distribution and potential theory.

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Homework Statement


Consider a very thin rod lying on the z axis from z = −L/2 to z = L/2. It carries a uniform charge density λ. Show that away from the rod, at the point r (r >>L), the potential can be written as V (r, θ) = (2Lλ/4πε0)(1/L)[ 1 + 1/3(L/2r)2P2(cos θ) + 1/3(L/2r)4 P4(cos θ) + · · ·# (1)

Homework Equations


special-techniques-teknik-khusus-11-728.jpg


The Attempt at a Solution


At the beginning, I tried to solve this question using cylindrical coordinates as there is some theta dependence in Legendre polynomial but it did not work.Then,I took the volume integral using cartesian coordinates and treating theta as constant.By doing that I could just take the Legendre polynomials out of the integration and calculate the integral with respect to z. I calculated the integral and put values of n up to n=4 and get the exact result in the square brackets but I have λL/4πε0r outside while I have to have 2λL/4πε0L.

What should I do know? Is my assumption,the theta is constant, true?

Thanks for your help...
 
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Check your algebra.
 
vela said:
Check your algebra.
thank you for your comment. the question is wrong, I informed today.
 

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