Multivariable Derivative Error

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The discussion centers around the function f(x,y) defined piecewise, with a focus on proving that it does not satisfy the limit condition for differentiability at the origin. Participants express confusion about the concept of E(v,h) and its implications for differentiability, noting that it should approach zero if the function is differentiable. Attempts to solve the problem using slope comparisons are questioned, as they may not be valid. A clarification is provided regarding the directional derivative and its necessary linearity conditions at the point (0,0). The conversation highlights the complexities of multivariable calculus and the need for a deeper understanding of the function's behavior near the origin.
Kitty Kat
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Homework Statement


f(x,y) =
(xy) / (x2 + y4), when (x, y) ≠ (0,0)
0, when (x,y) = (0,0)

Homework Equations


Explicitly show that f(x,y) does not satisfy
lim h -> 0 [ E(v,h) / ||h|| ] = 0 when v = 0
(h, v, and 0 are all vectors; I'm not sure how to put a hat on them)

The Attempt at a Solution


I have no idea how to actually tackle this problem using multivariable calculus methods so I just compared the slopes instead (not sure if this is a valid approach either).
Further more I don't really get the concept of E(v,h). All my professor said is that it should approach 0 if the function is differentiable. I'd really appreciate an explanation of E(v,h) please (:

f(h) = f(0,0) + (df/dx(0,0) * x) + (df/dy(0,0) * y) + E(h)
f(h) = 0 + 0x + 0y + E(h)
f(h) = E(h)

Let f(x,y) = f(h,h)
f(h,h) = h / (1+h2)
f'(h) = (-h2 + 1) / (1+h2)2

||h|| = 2h2
f'(||h||) = 4h

lim h-> 0 [ f'(h) / f'(||h||) ] = ∞
 
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Kitty Kat said:

Homework Statement


f(x,y) =
(xy) / (x2 + y4), when (x, y) ≠ (0,0)
0, when (x,y) = (0,0)

Homework Equations


Explicitly show that f(x,y) does not satisfy
lim h -> 0 [ E(v,h) / ||h|| ] = 0 when v = 0
(h, v, and 0 are all vectors; I'm not sure how to put a hat on them)

The Attempt at a Solution


I have no idea how to actually tackle this problem using multivariable calculus methods so I just compared the slopes instead (not sure if this is a valid approach either).
Further more I don't really get the concept of E(v,h). All my professor said is that it should approach 0 if the function is differentiable. I'd really appreciate an explanation of E(v,h) please (:

f(h) = f(0,0) + (df/dx(0,0) * x) + (df/dy(0,0) * y) + E(h)
f(h) = 0 + 0x + 0y + E(h)
f(h) = E(h)

Let f(x,y) = f(h,h)
f(h,h) = h / (1+h2)
f'(h) = (-h2 + 1) / (1+h2)2

||h|| = 2h2
f'(||h||) = 4h

lim h-> 0 [ f'(h) / f'(||h||) ] = ∞
Do you have a definition of E(v,h)?
 
SammyS said:
Do you have a definition of E(v,h)?
Not quite exactly. Here's a picture of my notes since I don't know how to type it here with proper notation.
Link: https://dl.pushbulletusercontent.com/wwTIGu5Cjgt9OlhFWP6geOc1nuuUgJJX/20151024_164749.jpg
20151024_164749.jpg
 
I get a virus warning when I try to open that.
 
Kitty Kat said:

Homework Statement


f(x,y) =
(xy) / (x2 + y4), when (x, y) ≠ (0,0)
0, when (x,y) = (0,0)

Homework Equations


Explicitly show that f(x,y) does not satisfy
lim h -> 0 [ E(v,h) / ||h|| ] = 0 when v = 0
(h, v, and 0 are all vectors; I'm not sure how to put a hat on them)

The Attempt at a Solution


I have no idea how to actually tackle this problem using multivariable calculus methods so I just compared the slopes instead (not sure if this is a valid approach either).
Further more I don't really get the concept of E(v,h). All my professor said is that it should approach 0 if the function is differentiable. I'd really appreciate an explanation of E(v,h) please (:

f(h) = f(0,0) + (df/dx(0,0) * x) + (df/dy(0,0) * y) + E(h)
f(h) = 0 + 0x + 0y + E(h)
f(h) = E(h)

Let f(x,y) = f(h,h)
f(h,h) = h / (1+h2)
f'(h) = (-h2 + 1) / (1+h2)2

||h|| = 2h2
f'(||h||) = 4h

lim h-> 0 [ f'(h) / f'(||h||) ] = ∞

Some of your equations make no sense, or else are not true for your current function. For example, your "formula" for ##f(h)## has only ##h## on one side and ##x,y## on the other; that does not mean anything. Besides that, even if we were to correct the formula, it might be false for your function, because it makes some assumptions about the nature of the function in a neighborhood of ##(0,0)## that may not hold for your ##f(x,y)##.

Basically, if we define the directional derivative of f at the point ##(x_0,y_0)## in the direction ##(p,q)## as
D_{(p,q)} f(x_0,y_0) = \lim_{t \to 0} \frac{f(x_0 + t p, y_0 + t q) - f(x_0,y_0)}{t},
then, in order for your result about ##E(h)## to hold, it is necessary (but perhaps not sufficient) that ##D_{(p,q)} f(x_0,y_0)## be linear in ##(p,q)##; that is, it would be necessary to have ##D_{(p,q)} f(x_0,y_0) = a p + b q## for some real numbers ##a## and ##b##. Is that true at ##(x_0,y_0) = (0,0)## in your current example?
 
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Kitty Kat said:
Furthermore, I don't really get the concept of E(v,h). All my professor said is that it should approach 0 if the function is differentiable. I'd really appreciate an explanation of E(v,h) please (:
Read this page: http://www.math.ku.edu/~lerner/m291F08/Chapter9.pdf
 
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