Muon travelling faster than the speed of light

Click For Summary

Homework Help Overview

The discussion revolves around the observation of a muon traveling a distance of 800 meters before disintegrating, with an initial calculation suggesting it traveled faster than the speed of light. Participants explore the implications of time dilation and the muon's lifetime in different reference frames.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants question the validity of the initial speed calculation and discuss the relevance of the muon's lifetime in its rest frame versus the laboratory frame. There is exploration of the Lorentz factor and its application in calculating the muon's speed.

Discussion Status

Several participants are engaged in calculating the muon's speed using different approaches and are sharing their results. There is an ongoing examination of the assumptions made regarding the muon's lifetime and the effects of relativistic physics, with some guidance being offered on the correct application of formulas.

Contextual Notes

Participants note that the muon lifetime is a mean value and that individual muons may vary in their actual lifetime. The discussion also highlights the need for clarity on which frame of reference is being used for calculations.

ehrenfest
Messages
2,001
Reaction score
1
A muon is observed to travel 800 meters before disintigrating. The lifetime of a muon is 2 * 10 ^ -6. So the observer concludes that the muon traveled at a speed of

4 * 10^8 m/s which is faster than c.

Why is the observer wrong?

I though it was impossible for anything to travel faster than light in any inertial reference. I don't see how you can get around the fact that the muon moved so far in that amount of time and at least its average velocity was faster than c.

I do not see where you can apply the Lorentz factor.
 
Physics news on Phys.org
The key is that that's the muon's lifetime in it's rest frame. Because of time dilation, it will observed to last longer than that when it's traveling close to the speed of light.
 
The lifetime in which frame?
 
Besides which the muon lifetime is only a mean lifetime. For a muon to last twice the mean is not a bit unusual. Don't assume all muons last exactly 2x10^(-6) sec. But the answer they are probably after is the one StatusX pointed out.
 
I see, StatusX. And you're right Dick this is a simplified problem.

So, if I want to calculate the actual speed of the muon, I want to set the rest frame time times the lorentz factor equal to the laboratory frame time. You can solve for v and get v = 2.078 * 10^8, if my calculations are valid.
 
I get more like 1.98*10^8, but that's close enough.
 
Dick said:
I get more like 1.98*10^8, but that's close enough.

No. Let's figure this out.

I solved,

t_lab = 2*10^-6/(1- 800^2/(t^2*c^2))
for t to get

t = 3.848 * 10 ^ -6.

I then divided 800 by that.
 
Where's the sqrt in your gamma factor? Try t_lab=t_rest/sqrt(1-v^2/c^2) and solve for v.
 
Last edited:
Sorry. That's foolish. You don't know t_lab. As you said with some stuff fixed, t=t_rest/sqrt(1-d^2/(t^2*c^2)). But now I get 2.40*10^8 m/s.
 
Last edited:
  • #10
I'm getting exactly v = 2.4 * 10^8 m/s
 
  • #11
learningphysics said:
I'm getting exactly v = 2.4 * 10^8 m/s

That's a bingo!
 
  • #12
Dick said:
Where's the sqrt in your gamma factor? Try t_lab=t_rest/sqrt(1-v^2/c^2) and solve for v.

Yes. Adding the square root gets me 2.4 * 10 ^ 8. Thanks.
 

Similar threads

Replies
10
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 0 ·
Replies
0
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 0 ·
Replies
0
Views
4K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 27 ·
Replies
27
Views
3K
  • · Replies 2 ·
Replies
2
Views
248
  • · Replies 6 ·
Replies
6
Views
2K